{"id":9152,"date":"2019-02-05T07:11:21","date_gmt":"2019-02-05T07:11:21","guid":{"rendered":"https:\/\/dbtut.com\/?p=9152"},"modified":"2019-02-05T07:11:21","modified_gmt":"2019-02-05T07:11:21","slug":"the-insert-statement-conflicted-with-the-foreign-key-constraint","status":"publish","type":"post","link":"https:\/\/dbtut.com\/index.php\/2019\/02\/05\/the-insert-statement-conflicted-with-the-foreign-key-constraint\/","title":{"rendered":"The INSERT statement conflicted with the FOREIGN KEY constraint"},"content":{"rendered":"<p>&nbsp;<\/p>\n<p>You can get this error when you want to inset data into a table that has the Foreing Key. It means that there is no relevant record in the Primary table that Foreign Key is linked to. The record must first be added to the primary table.<\/p>\n<p>Let&#8217;s make an example for a better understanding.<\/p>\n<p><strong>Example:<\/strong><\/p>\n<p>We create two tables as follows. In the Person table we set the ID column as Primary Key.<\/p>\n<pre class=\"lang:default decode:true\">CREATE TABLE [dbo].[Person](\r\n[ID] [int] IDENTITY(1,1) NOT NULL,\r\n[Name] [varchar](50) NULL,\r\n\u00a0CONSTRAINT [PK_Person] PRIMARY KEY CLUSTERED\r\n(\r\n[ID] ASC\r\n)\r\n) ON [PRIMARY]\r\nGO\r\nCREATE TABLE [dbo].[PersonDetails](\r\n[ID] [int] IDENTITY(1,1) NOT NULL,\r\n[PersonID] int NOT NULL,\r\n[SurName] [varchar](50) NULL,\r\n[Age] int\r\n) ON [PRIMARY]\r\nGO<\/pre>\n<p>Now let&#8217;s set the PersonID column in the PersonDetails table as the Foreign Key of the Primary Key in the Person table.<\/p>\n<pre class=\"lang:default decode:true\">ALTER TABLE [dbo].[PersonDetails]\u00a0 WITH CHECK ADD\u00a0 CONSTRAINT [FK_PersonDetails_Person] FOREIGN KEY([PersonID])\r\nREFERENCES [dbo].[Person] ([ID])\r\nGO\r\nALTER TABLE [dbo].[PersonDetails] CHECK CONSTRAINT [FK_PersonDetails_Person]\r\nGO<\/pre>\n<p>Then, when there is no record in the Primary table, try to add a record to the Foreign table.<\/p>\n<pre class=\"lang:default decode:true\">USE [TestDB]\r\nGO\r\nINSERT INTO [dbo].[PersonDetails] ([PersonID],[SurName],[Age]) VALUES (1,'CAKIR',34)\r\nGO<\/pre>\n<p>We&#8217;ll get the error as follows. Because the Primary table does not have the corresponding ID value.<\/p>\n<p><span style=\"color: #ff0000;\"><em>Msg 547, Level 16, State 0, Line 3<\/em><\/span><\/p>\n<p><span style=\"color: #ff0000;\"><em>The INSERT statement conflicted with the FOREIGN KEY constraint &#8220;FK_PersonDetails_Person&#8221;.<\/em><\/span><\/p>\n<p><span style=\"color: #ff0000;\"><em>The conflict occurred in database &#8220;TestDB&#8221;, table &#8220;dbo.Person&#8221;, column &#8216;ID&#8217;.<\/em><\/span><\/p>\n<p><span style=\"color: #ff0000;\"><em>The statement has been terminated.<\/em><\/span><\/p>\n<p id=\"HTpKawT\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-9154  aligncenter\" src=\"https:\/\/dbtut.com\/wp-content\/uploads\/2019\/02\/img_5c59368f501f9.png\" alt=\"\" width=\"762\" height=\"236\" \/><\/p>\n<p>If we add a record to the primary table first, the process of adding records to the foreign table will also be completed successfully.<\/p>\n<pre class=\"lang:default decode:true\">USE [TestDB]\r\nGO\r\nINSERT INTO [dbo].[Person] ([ID],[Name]) VALUES (1,'Nurullah')\r\nGO\r\nINSERT INTO [dbo].[PersonDetails] ([PersonID],[SurName],[Age]) VALUES (1,'CAKIR',34)\r\nGO<\/pre>\n<p id=\"lHmHHyW\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-9156  aligncenter\" src=\"https:\/\/dbtut.com\/wp-content\/uploads\/2019\/02\/img_5c5936b8482cd.png\" alt=\"\" width=\"744\" height=\"246\" \/><\/p>\n\n<div class=\"pvc_clear\"><\/div>\n<p id=\"pvc_stats_9152\" class=\"pvc_stats all  \" data-element-id=\"9152\" style=\"\"><i class=\"pvc-stats-icon medium\" aria-hidden=\"true\"><svg aria-hidden=\"true\" focusable=\"false\" data-prefix=\"far\" data-icon=\"chart-bar\" role=\"img\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 512 512\" class=\"svg-inline--fa fa-chart-bar fa-w-16 fa-2x\"><path fill=\"currentColor\" d=\"M396.8 352h22.4c6.4 0 12.8-6.4 12.8-12.8V108.8c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v230.4c0 6.4 6.4 12.8 12.8 12.8zm-192 0h22.4c6.4 0 12.8-6.4 12.8-12.8V140.8c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v198.4c0 6.4 6.4 12.8 12.8 12.8zm96 0h22.4c6.4 0 12.8-6.4 12.8-12.8V204.8c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v134.4c0 6.4 6.4 12.8 12.8 12.8zM496 400H48V80c0-8.84-7.16-16-16-16H16C7.16 64 0 71.16 0 80v336c0 17.67 14.33 32 32 32h464c8.84 0 16-7.16 16-16v-16c0-8.84-7.16-16-16-16zm-387.2-48h22.4c6.4 0 12.8-6.4 12.8-12.8v-70.4c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v70.4c0 6.4 6.4 12.8 12.8 12.8z\" class=\"\"><\/path><\/svg><\/i> <img loading=\"lazy\" decoding=\"async\" width=\"16\" height=\"16\" alt=\"Loading\" src=\"https:\/\/dbtut.com\/wp-content\/plugins\/page-views-count\/ajax-loader-2x.gif\" border=0 \/><\/p>\n<div class=\"pvc_clear\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>&nbsp; You can get this error when you want to inset data into a table that has the Foreing Key. It means that there is no relevant record in the Primary table that Foreign Key is linked to. The record must first be added to the primary table. Let&#8217;s make an example for a better &hellip;<\/p>\n<div class=\"pvc_clear\"><\/div>\n<p id=\"pvc_stats_9152\" class=\"pvc_stats all  \" data-element-id=\"9152\" style=\"\"><i class=\"pvc-stats-icon medium\" aria-hidden=\"true\"><svg aria-hidden=\"true\" focusable=\"false\" data-prefix=\"far\" data-icon=\"chart-bar\" role=\"img\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 512 512\" class=\"svg-inline--fa fa-chart-bar fa-w-16 fa-2x\"><path fill=\"currentColor\" d=\"M396.8 352h22.4c6.4 0 12.8-6.4 12.8-12.8V108.8c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v230.4c0 6.4 6.4 12.8 12.8 12.8zm-192 0h22.4c6.4 0 12.8-6.4 12.8-12.8V140.8c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v198.4c0 6.4 6.4 12.8 12.8 12.8zm96 0h22.4c6.4 0 12.8-6.4 12.8-12.8V204.8c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v134.4c0 6.4 6.4 12.8 12.8 12.8zM496 400H48V80c0-8.84-7.16-16-16-16H16C7.16 64 0 71.16 0 80v336c0 17.67 14.33 32 32 32h464c8.84 0 16-7.16 16-16v-16c0-8.84-7.16-16-16-16zm-387.2-48h22.4c6.4 0 12.8-6.4 12.8-12.8v-70.4c0-6.4-6.4-12.8-12.8-12.8h-22.4c-6.4 0-12.8 6.4-12.8 12.8v70.4c0 6.4 6.4 12.8 12.8 12.8z\" class=\"\"><\/path><\/svg><\/i> <img loading=\"lazy\" decoding=\"async\" width=\"16\" height=\"16\" alt=\"Loading\" src=\"https:\/\/dbtut.com\/wp-content\/plugins\/page-views-count\/ajax-loader-2x.gif\" border=0 \/><\/p>\n<div class=\"pvc_clear\"><\/div>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_uf_show_specific_survey":0,"_uf_disable_surveys":false,"footnotes":""},"categories":[3,1596],"tags":[1925,1924],"class_list":["post-9152","post","type-post","status-publish","format-standard","","category-mssql","category-tsql","tag-cannot-insert-foreign-table","tag-the-conflict-occurred-in-database"],"aioseo_notices":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v24.9 - 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